> Ok,if these are the facts: char *arg;
> arg = "d+3";
>
> How come the if statment: if ( (*(arg+1) != '+'))
> { /* whatever */ }
>
> Always returns true, ie even though the second char in the argument is '+',
> { /* whatever */ ) is still executed?
Can you give us more context? If the code fragment literally says:
void foo()
{
char *arg;
arg = "d+3";
if ( (*(arg+1) != '+'))
{ /* whatever */ }
}
Then, yes, /* whatever */ shouldn't be executed. But if you're doing
something more complex, like passing arguments between functions, you
could be making some other error that you're not showing us.
Jeremy
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