Ok heres the truth table I'm looking for... 1 0 A 1 0 1 0 0 0 B thus A = 0110 B = 1100 C = 1000 - this would be the effect (C has what B does but not A..ugh) I think what Rob Baumstark said would work... C = B-(A^B) Gunna have to try that > > if this isn't what you need, could you supply a truth table for us to look >over? > > 1 0 A >1 0 1 > >0 1 0 > >B > >--Angus *>-Jon-<* _________________________________________________________________________ "I have traveled the length and breadth of this country and talked with the best people, and I can assure you that data processing is a fad that won't last out the year." --The editor in charge of business books for Prentice Hall, 1957 +------------------------------------------------------------+ | Ensure that you have read the CircleMUD Mailing List FAQ: | | http://democracy.queensu.ca/~fletcher/Circle/list-faq.html | +------------------------------------------------------------+
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