This is a simple drop-in tid-bit of code that returns the number of items
that someone is in possession of. It counts through containers recursively
so that if someone puts 14 things in a sack that is put in a sack that is
put in a sack that is put in a sack that is put in a sack that is put in a
sack that is put in a sack, it will still count the 14 items and all of
the sacks.
----------
File: utils.h
----------
int item_count(struct char_data *ch);
----------
File: utils.c
----------
/* Will return the number of items in the container. */
int count_contents(struct obj_data *container)
{
int count = 0;
struct obj_data *obj;
if (container->contains)
for (obj = container->contains; obj; obj = obj->next_content, count++)
if (GET_OBJ_TYPE(obj) == ITEM_CONTAINER && obj->contains)
count += count_contents(obj);
return(count);
}
/* Will return the number of items that the character owns. */
int item_count(struct char_data *ch)
{
int i, count = 0;
struct obj_data *obj;
for (i = 0; i < NUM_WEARS; i++) {
if (GET_EQ(ch, i)) {
count++;
if (GET_OBJ_TYPE(GET_EQ(ch, i)) == ITEM_CONTAINER &&
GET_EQ(ch, i)->contains)
count += count_contents(GET_EQ(ch, i));
}
}
if (ch->carrying)
for (obj = ch->carrying; obj; obj = obj->next_content, count++)
if (GET_OBJ_TYPE(obj) == ITEM_CONTAINER && obj->contains)
count += count_contents(obj);
return(count);
}
That allows you to do something similar to the following in do_score():
sprintf(buf, "You possess %d items.\r\n", item_count(ch));
send_to_char(buf, ch);
Easy enough, eh?
John Evans <evansj@datawest.net>
http://www.hi-line.net/~evansj/ telnet://spear.gator.net:1066
Any sufficiently advanced technology is indistinguishable from magic.
--Arthur C. Clarke
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