-----Original Message----- From: Brandon Lees (Whitlock) <brandon@SCI.BROOKLYN.CUNY.EDU> To: CIRCLE@post.queensu.ca <CIRCLE@post.queensu.ca> Date: Monday, November 02, 1998 6:54 PM Subject: do_look >I want 2 change do_look so that if there is more than one of an item >it will be listed as <2x> a sword instead of being listed twice. Any >suggestions on how to go about doing this? This is not my code, it's a snippet from somewhere. Rick From: Brian Williams <bmw@efn.org> Subject: Object Stacking code void list_obj_to_char(struct obj_data * list, struct char_data * ch, int mode, bool show) { struct obj_data *i, *j; char buf[10]; bool found; int num; found = FALSE; for (i = list; i; i = i->next_content) { num = 0; for (j = list; j != i; j = j->next_content) if (j->item_number==NOTHING) { if(strcmp(j->short_description,i->short_description)==0) break; } else if (j->item_number==i->item_number) break; if (j!=i) continue; for (j = i; j; j = j->next_content) if (j->item_number==NOTHING) { if(strcmp(j->short_description,i->short_description)==0) num++; } else if (j->item_number==i->item_number) num++; if (CAN_SEE_OBJ(ch, i)) { if (num!=1) { sprintf(buf,"(%2i) ",num); send_to_char(buf,ch); } show_obj_to_char(i, ch, mode); found = TRUE; } } if (!found && show) send_to_char(" Nothing.\r\n", ch); } +------------------------------------------------------------+ | Ensure that you have read the CircleMUD Mailing List FAQ: | | http://democracy.queensu.ca/~fletcher/Circle/list-faq.html | +------------------------------------------------------------+
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