I am using the following code to show a character a room: void character::showroom(room *r){ character *ch; string buf; if(!r) r = in; (buf = r->name) += "\r\n"; if(!(flags.test(BRIEF))) (buf += r->description) += "\r\n"; for(ch = r->people; ch != NULL; ch = ch->roomnext) if(ch != this) buf += ch->show(this); buf += "\r\n"; if(flags.test(AUTOEXIT)){ for(int i = 0; i < NUMDIRS; i++) if(r->exits[i]) ((buf += dirs[i]) += r->exits[i]->name) += "\r\n\r\n"; } *this << buf.pointer; } *this << buf.pointer should send the contents of buf to the character (*this << "Huh?\r\n"; works fine) I get the following compile error, however: C:\Dynamic\src\character.cpp(268) : error C2274: 'function-style cast' : illegal as right side of '.' operator I looked at the documentation for the error, and it says I should use the operator keyword before pointer, but buf.operator pointer causes a ton of errors. Any help appreciated, ^Blaize^ ________________________________________________________________ GET INTERNET ACCESS FROM JUNO! Juno offers FREE or PREMIUM Internet access for less! Join Juno today! For your FREE software, visit: http://dl.www.juno.com/get/web/. -- +---------------------------------------------------------------+ | FAQ: http://qsilver.queensu.ca/~fletchra/Circle/list-faq.html | | Archives: http://post.queensu.ca/listserv/wwwarch/circle.html | | Newbie List: http://groups.yahoo.com/group/circle-newbies/ | +---------------------------------------------------------------+
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